C\u00f2n n\u1ebfu kh\u00f4ng \u1ea5n t\u01b0\u1ee3ng v\u1edbi con n\u00e0o, anh em n\u00ean xem th\u1ed1ng k\u00ea trong 100 ng\u00e0y. T\u00ecm xem con l\u00f4 n\u00e0o trong 4 con 52, 28, 86, 60 hay v\u1ec1 nh\u1ea5t th\u00ec h\u00e3y ch\u1ecdn n\u00f3. \u0110\u00e2y l\u00e0 kinh nghi\u1ec7m x\u01b0\u01a1ng m\u00e1u c\u1ee7a admin khi ch\u1ecdn b\u1ea1ch th\u1ee7.<\/p>\n
Khi \u0111\u00e3 t\u00ecm ra 1 con duy nh\u1ea5t. Anh em h\u00e3y \u0111\u00e1nh ngay con l\u00f4 \u0111\u00f3 v\u00e0 \u0111\u00e1nh 1 ng\u00e0y duy nh\u1ea5t. T\u1ef7 l\u1ec7 chi\u1ebfn th\u1eafng r\u1ea5t cao. Admin c\u0169ng s\u1eed d\u1ee5ng \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n xsmb<\/strong> h\u00e0ng ng\u00e0y.<\/p>\n2. B\u1ea1ch th\u1ee7 mi\u1ec1n B\u1eafc l\u00f4 K\u00e9p<\/h3>\n
Ch\u00fang ta \u0111\u1ec1u bi\u1ebft r\u1eb1ng ch\u01a1i L\u00f4 K\u00e9p s\u1ebd l\u00e0 s\u1ef1 m\u1ea1o hi\u1ec3m v\u00f4 c\u00f9ng l\u1edbn. Nh\u01b0ng n\u1ebfu \u00e1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y th\u00ec t\u1ef7 l\u1ec7 chi\u1ebfn th\u1eafng c\u0169ng r\u1ea5t kh\u1ea3 quan. Anh em h\u00e3y xem \u0111\u1ec3 soi c\u1ea7u b\u1ea1ch th\u1ee7 mi\u1ec1n b\u1eafc cho ch\u00ednh x\u00e1c l\u00f4 k\u00e9p.<\/p>\n
V\u00ed D\u1ee5: Ch\u00fang ta th\u1ed1ng k\u00ea 27 l\u00f4 c\u1ee7a ng\u00e0y h\u00f4m nay theo \u0111\u1ea7u s\u1ed1 v\u00e0 k\u1ebft qu\u1ea3 nh\u01b0 sau:<\/p>\n
\n\n\n\u0110\u1ea7u 0<\/strong><\/td>\n07; 08<\/td>\n<\/tr>\n | \n\u0110\u1ea7u 1<\/strong><\/td>\n12; 16<\/td>\n<\/tr>\n | \n\u0110\u1ea7u 2<\/strong><\/td>\n<\/td>\n<\/tr>\n | \n\u0110\u1ea7u 3<\/strong><\/td>\n32; 37; 39<\/td>\n<\/tr>\n | \n\u0110\u1ea7u 4<\/strong><\/td>\n44; 45; 46; 47<\/td>\n<\/tr>\n | \n\u0110\u1ea7u 5<\/strong><\/td>\n50; 52; 53; 55; 55<\/td>\n<\/tr>\n | \n\u0110\u1ea7u 6<\/strong><\/td>\n61; 64; 67<\/td>\n<\/tr>\n | \n\u0110\u1ea7u 7<\/strong><\/td>\n77<\/td>\n<\/tr>\n | \n\u0110\u1ea7u 8<\/strong><\/td>\n80; 83; 84<\/td>\n<\/tr>\n | \n\u0110\u1ea7u 9<\/strong><\/td>\n91; 95; 97; 99<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n Trong b\u1ea3ng th\u1ed1ng k\u00ea b\u00ean tr\u00ean anh em th\u1ea5y \u0110\u1ea7u 2 C\u00e2m. V\u1eady b\u1ea1ch th\u1ee7 h\u00f4m sau ch\u00fang ta s\u1ebd \u0111\u00e1nh ch\u00ednh l\u00e0 con 22<\/strong>.<\/p>\nNghe c\u00f3 v\u1ebb \u0111i\u00ean r\u1ed3 nh\u01b0ng tr\u00ean th\u1ef1c t\u1ebf c\u00e1ch b\u1eaft k\u00e9p n\u00e0y \u0111\u00e3 th\u1ef1c s\u1ef1 hi\u1ec7u qu\u1ea3. Anh em h\u00e3y th\u1eed ki\u1ec3m tra nh\u00e9.<\/p>\n 3. B\u1ea1ch th\u1ee7 mi\u1ec1n B\u1eafc L\u00f4 T\u00e2m Linh<\/h3>\nTh\u1ef1c t\u1ebf th\u00ec \u0111\u00e2y kh\u00f4ng ph\u1ea3i l\u00e0 c\u00e1ch soi c\u1ea7u. \u0110\u00e2y l\u00e0 m\u1ed9t ph\u01b0\u01a1ng \u00e1n khi m\u00e0 kh\u00f4ng c\u00f3 c\u00e1ch soi c\u1ea7u n\u00e0o n\u1eefa th\u00ec l\u00e0m th\u00f4i. N\u00ean anh em h\u00e3y tham kh\u1ea3o, c\u00f2n khuy\u00ean th\u00ec admin kh\u00f4ng khuy\u1ebfn kh\u00edch. (c\u00e1ch n\u00e0y do ng\u01b0\u1eddi ch\u01a1i g\u1eedi cho admin nh\u1edd chia s\u1ebb cho anh em)<\/em><\/p>\nC\u00e1ch t\u00ecm: Anh em h\u00f4m nay \u0111\u1ecbnh ch\u01a1i con B\u1ea1ch th\u1ee7 l\u00f4 10 \u0111i\u1ec3m<\/strong> ch\u1eb3ng h\u1ea1n.<\/p>\n10 \u0111i\u1ec3m = 230k \u0111\u00fang kh\u00f4ng.<\/p>\n Anh em l\u1ea5y 230k \u0111\u1ecbnh ch\u01a1i ra, xem t\u1ea5t c\u1ea3 c\u00f3 bao nhi\u1ec1u t\u1edd, m\u1ed7i t\u1edd l\u1ea5y 2 s\u1ed1 seri cu\u1ed1i. Ch\u00fang ta s\u1ebd g\u1ecdi l\u00e0 AB.<\/p>\n T\u1edd 1 c\u00f3 2 s\u1ed1 seri cu\u1ed1i AB(1).<\/strong> \nT\u1edd 2 c\u00f3 2 s\u1ed1 seri cu\u1ed1i AB(2).<\/strong> \nT\u1edd 3 c\u00f3 2 s\u1ed1 seri cu\u1ed1i AB(3).<\/strong> \n\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.. \nAnh em c\u1ed9ng t\u1ea5t c\u1ea3 AB(1)<\/strong> + AB (2)<\/strong> + AB (3)<\/strong> +\u2026\u2026\u2026\u2026AB (N)<\/strong> = T\u1ed5ng.<\/strong><\/p>\nSau \u0111\u00f3 anh em l\u1ea5y T\u1ed5ng<\/strong> chia cho s\u1ed1 t\u1edd<\/strong>: T\u1ed5ng \/ N = B\u1ea1ch th\u1ee7 l\u00f4<\/strong>.<\/p>\nC\u00e1ch n\u00e0y l\u00e0 c\u00e1ch khi anh em th\u1ef1c s\u1ef1 qu\u00e1 b\u00ed kh\u00f4ng t\u00ecm ra b\u1ea1ch th\u1ee7 l\u00f4 n\u00e0o. V\u00ec th\u1ef1c t\u1ebf n\u00f3 c\u0169ng ch\u1eb3ng g\u1ecdi l\u00e0 soi c\u1ea7u b\u1ea1ch th\u1ee7 mi\u1ec1n b\u1eafc g\u00ec, nh\u01b0ng \u0111\u00e2y l\u00e0 m\u1ed9t c\u00e1ch t\u00e2m linh hay v\u00e0 kh\u00e1 ch\u00ednh x\u00e1c.<\/p>\n K\u1ebft Th\u00fac<\/h3>\nC\u00f3 r\u1ea5t nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u. M\u1ed7i ph\u01b0\u01a1ng ph\u00e1p \u0111\u1ec1u mang l\u1ea1i gi\u00e1 tr\u1ecb v\u00f4 c\u00f9ng to l\u1edbn cho ng\u01b0\u1eddi th\u1ef1c hi\u1ec7n. Anh em h\u00e3y tham kh\u1ea3o b\u00ean tr\u00ean l\u00e0 3 ph\u01b0\u01a1ng ph\u00e1p b\u1eaft b\u1ea1ch th\u1ee7 mi\u1ec1n B\u1eafc ch\u00ednh x\u00e1c h\u00f4m nay.<\/p>\n H\u00e3y tr\u1ea3i nghi\u1ec7m v\u00e0 anh em s\u1ebd nh\u1eadn th\u1ea5y k\u1ebft qu\u1ea3 v\u00f4 c\u00f9ng th\u1ecfa m\u00e3n. Ch\u00fac anh em lu\u00f4n may m\u1eafn v\u00e0 chi\u1ebfn th\u1eafng.<\/p>\n<\/div>\n<\/div>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n <\/main><\/p>\n \n soi c\u1ea7u cao c\u1ea5p<\/span><\/div>\n<\/div>\n | | | | | | | | | | |